9 / 10
Interactive Explore

Festival Crew Power Calculator

Festival context —The Cry of Jelicuon venue must be cleared after each school performs. Set the total work done by the crew and the time available. See the power output required — and discover why a faster cleanup demands so much more from every worker.

S9FE-IIIa-22Grade 9 · Quarter 3Explain the Relationship of Power, Work, and Time

Festival Crew Power Calculator

Interactive Simulator
"The Cry of Jelicuon venue must be cleared after each school performs. Set the total work done by the crew and the time available. See the power output required — and discover why a faster cleanup demands so much more from every worker."

Festival Crew Power Race

startstartCREW ATime — 60 sPOWER P = W / t20.0 W1200 J ÷ 60 s0% clearedwork = 0 J doneCREW BTime — 30 sPOWER P = W / t40.0 W1200 J ÷ 30 s0% clearedS9FE-IIIa-22

Same work, less time → more power. Set both crews equal to see the powers match.

Adjust Variables

Total work to clear (J)1200 J
1005000
Crew A — time available (s)60 s
10300
Crew B — time available (s)30 s
5300

Physics ReadoutsLIVE

Crew A Power20.0 W
Crew B Power40.0 W
Power Ratio2.00×
power = work / time

Community Hub — Cultural Discussion

Reflect & Connect

The festival director cuts the prop-clearing window from 15 minutes to 8 minutes between performances. Using the power formula, calculate how much more power the crew must output to finish on time with the same total work. What are the physical and safety implications of doubling the required power output? How would you redesign the post-performance workflow to make it more manageable?

Discuss with your class or write your response in your science journal.

Performance Task

Measure Your Own Stair-Climbing Power

1Do

Find a staircase. Climb it once at a slow steady pace, then once as fast as is safe. Have a partner time each climb with a stopwatch. Do NOT run if the stairs are wet or crowded.

2Measure

Measure the total vertical height climbed (count the steps and multiply by about 0.18 m per step). Record your body mass. Compute the work done against gravity W = m·g·h (g = 9.8 m/s²), then power P = W ÷ time for both the slow and the fast climb.

3Reflect

Same height, same work — but the faster climb required more power because P = W/t. This is competency S9FE-IIIa-22. In the Cry of Jelicuon, the cleanup crew does the same total work whether the window is 15 or 8 minutes, but the shorter window demands far more power. Using your two numbers, by what factor did your power output increase when you climbed faster?

Record your measurements and reflections in your science journal.