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The Arc of a Bolo: 2D Motion in the War Reenactment

Festival context —Performers running formations, timed stage entrances, and prop throws during the Cry of Jelicuon reenactment

S9FE-IIc-18Grade 9 · Quarter 2Analyze Motion in Two Dimensions

When a Prop Takes Flight: Horizontal and Vertical Motion Together

One of the most dramatic moments in the Cry of Jelicuon reenactment involves performers throwing prop weapons (bolos, rifles) in choreographed arcs. What the audience sees as a graceful curve is actually two completely independent motions happening simultaneously: horizontal and vertical.

In two-dimensional projectile motion, the horizontal component moves at constant velocity (no air resistance assumed) while the vertical component accelerates downward at g = 9.8 m/s². These two components are independent — changing one does not affect the other.

Comprehension Check

During a prop throw, the horizontal velocity remains throughout the flight (ignoring air resistance).

Performers jumping from risers also demonstrate this principle. The jump's launch angle determines the balance between horizontal distance (range) and maximum height. A 45° angle gives maximum range on level ground — useful for choreographing dramatic leaps across the stage.

Riser Jumps and Independent Motion Components

When a performer leaps from the top of an elevated riser during the Cry of Jelicuon, their body simultaneously undergoes two independent motions: horizontal displacement driven by their launch momentum, and vertical free-fall driven by gravity. At the peak of the jump, vertical velocity reaches zero for a brief instant — but horizontal velocity remains unchanged. This separation of components is why performers can cover significant horizontal distance while still clearing the stage floor safely. The choreographer exploits this physics deliberately: timing the jump so horizontal travel lands the performer at a precise formation mark.

Worked Example: Projectile Range
Given
v₀=8 m/sθ=45°g=9.8 m/s²
1Formularange = (v₀² × sin(2θ)) / g
2Substituterange = (64 × sin(90°)) / 9.8 = 64 / 9.8
3Answerrange ≈ 6.5 m

A prop thrown at 45° with initial speed 8 m/s travels about 6.5 m horizontally — enough to cross from one side of the stage to the center mark.

Comprehension Check

The curved path followed by a thrown prop is called a trajectory.